c^2+13c+12=0

Solution for c^2+13c+12=0 equation:

Simplifying
c2 + 13c + 12 = 0

Reorder the terms:
12 + 13c + c2 = 0

Solving
12 + 13c + c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(12 + c)(1 + c) = 0

Subproblem 1
Set the factor '(12 + c)' equal to zero and attempt to solve:

Simplifying
12 + c = 0

Solving
12 + c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-12' to each side of the equation.
12 + -12 + c = 0 + -12

Combine like terms: 12 + -12 = 0
0 + c = 0 + -12
c = 0 + -12

Combine like terms: 0 + -12 = -12
c = -12

Simplifying
c = -12
Subproblem 2
Set the factor '(1 + c)' equal to zero and attempt to solve:

Simplifying
1 + c = 0

Solving
1 + c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + c = 0 + -1

Combine like terms: 1 + -1 = 0
0 + c = 0 + -1
c = 0 + -1

Combine like terms: 0 + -1 = -1
c = -1

Simplifying
c = -1
Solution
c = {-12, -1}